[LARTC] about default filter command

[Vincent Dautremont]

Hi,
here I have another newcomer question :-)
in the section 9.6.1 of this how too
http://tldp.org/HOWTO/Adv-Routing-HOWTO/lartc.qdisc.filters.html
we can read commands about filters :
------------------------------------------

# tc filter add dev eth0 protocol ip parent 10: prio 1 u32 match \
   ip dport 22 0xffff flowid 10:1
# tc filter add dev eth0 protocol ip parent 10: prio 1 u32 match \
   ip sport 80 0xffff flowid 10:1
# tc filter add dev eth0 protocol ip parent 10: prio 2 flowid 10:2
What does this say? It says: attach to eth0, node 10: a priority 1  
u32 filter that matches on IP destination port 22 *exactly* and send  
it to band 10:1. And it then repeats the same for source port 80. The  
last command says that anything unmatched so far should go to band  
10:2, the next-highest priority.

------------------------------------------

i try to do this at home as i want my ssh traffic prioritary to other  
traffic but the problem is with the last command ! it simply don't  
work. The last command that says default trafic goes to prio 2  
doesn't work

# tc filter add dev eth0 protocol ip parent 10: prio 2 flowid 10:2

just give me the error: "Unknown filter flowid, hence option 1:2 is  
unparsable"

So I don't get what do I must do in order to say that the default  
trafic goes on priority 2 of the prio filter

is this how too always valid with the current version of tc ? did i  
do something wrong ?

Thank you for your help.



Vincent.

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