[LARTC] match'ing packets by size

Ethy H. Brito ethy.brito at inexo.com.br
Mon Dec 19 13:43:55 CET 2005


I visited yesican.chsoft.biz and the author proposes a way to match packets by
less than some size .

Here is the thing:

match u16 0x0000 0xffb0 at 2

With this match he says that packet with less than 80 bytes will match the rule.

Well, 0xffb0 translates to 1111 1111 1011 0000 (which is -80 BTW).

So, if I am correct any packet with bits 4 and/or 5 set (together with any of
the 4 LSB's) will break the rule. They will still be less than 80 bytes.

If it is so, packets of lenght, for instance,  16, 32 or 48 (32+16) will not make it.

I think the proposed solution only works with (2^n)-1 sized packets.
Am I correct or I completely misunderstood it?

Regards

-- 

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