[LARTC] How to set a host with public IP within a private network?
xerces8
xerces8 at butn.net
Wed Aug 3 12:09:09 CEST 2005
I would try this :
- assign the IP to PC (and 192.168.0.1 as gateway)
On the router:
- set up NAT to not touch packets sent to/from that IP
- set up a route to that IP thru eth1
(do not complicate :-)
-----Original Message-----
From: panca sorin <psihozefir at yahoo.com>
To: lartc at mailman.ds9a.nl
Date: Tue, 2 Aug 2005 10:38:37 -0700 (PDT)
Subject: [LARTC] How to set a host with public IP within a private network?
> Hello! I have the following setup:
> 1) a connection to my ISP with a public IP (1.2.3.4)
> with the gateway 1.2.3.1
> 2) an allocated IP class with 64 addresses
> (5.6.7.192/26)
> 3) two LANs connected through two NICs:
> a) 192.168.0.0/24 on eth1 (192.168.0.1)
> b) 10.0.0.0/24 on eth2 (10.0.0.1)
>
> The IPs from the allocated class are all assigned to
> eth0.
> The networks are SNATed to the external IP and to all
> IPs in the allocated class in a round-robin fashion.
> (-j SNAT --to 1.2.3.4 lowest_IP_in_class
> highest_IP_in_class)
>
> My question is:
> Is it possible to assign one IP from my allocated
> class to an internal machine without changing eth1 or
> eth2 IPs *OR* without adding a subclass of my
> allocated class to eth1 or eth2 in order to give an ip
> to an internal networked machine?
> What command should i give if that setup is possible?
> Desired Network Diagram:
>
> ----------
> /---|Internet|
> | ----------
> |eth0 192.168.0.1 10.0.0.1
> | ---------- eth1 eth2
> \--| Linux |--------------v--------------------v
> | Router | | |
> ---------- | |
> | |
> ------------- | ---------- |
> |192.168.0.2|--------< |10.0.0.2|----<
> ------------- | ---------- |
> . | . |
> . | . |
> . | . |
> --------------- | ------------ |
> |192.168.0.254|-------< |10.0.0.254|--<
> --------------- | ------------
> |
> |
> ----------- |
> |5.6.7.201|-----------<
> -----------
>
> I would de-assign some of the addresses from eth0 to
> re-assign them to locally connected computers...
>
> Thank you in advance for your help!
>
>
>
>
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